In terms of polar of the following order is correct ?

Options

A. `NH_(3)ltH_(2)OgtHFltH_(2)S`
B. `H_(2)SltNH_(3)ltH_(2)OltHF`
C. `H_(2)OltNH_(3)ltH_(2)SltHF`
D. `HFltH_(2)OltNH_(3)ltH_(2)O`

Explanation

To determine the order of polarity for the compounds NH3 (ammonia), H2O (water), HF (hydrogen fluoride), and H2S (hydrogen sulfide), we will follow these steps:

### Step 1: Identify the Central Atoms and Their Electronegativity
- **NH3**: The central atom is nitrogen (N) with an electronegativity of 3.04.
- **H2O**: The central atom is oxygen (O) with an electronegativity of 3.44.
- **HF**: The central atom is fluorine (F) with an electronegativity of 3.98.
- **H2S**: The central atom is sulfur (S) with an electronegativity of 2.58.

### Step 2: Compare Electronegativity Values
- **Fluorine (F)**: 3.98 (most electronegative)
- **Oxygen (O)**: 3.44
- **Nitrogen (N)**: 3.04
- **Sulfur (S)**: 2.58 (least electronegative)

### Step 3: Determine the Polarity Based on Electronegativity Differences
- The greater the difference in electronegativity between the central atom and hydrogen, the more polar the bond will be.
- Calculate the differences:
- **HF**: |3.98 - 2.20| = 1.78
- **H2O**: |3.44 - 2.20| = 1.24
- **NH3**: |3.04 - 2.20| = 0.84
- **H2S**: |2.58 - 2.20| = 0.38

### Step 4: Order the Compounds Based on Polarity
- Based on the electronegativity differences calculated, the order of polarity from highest to lowest is:
1. **HF** (highest polarity)
2. **H2O**
3. **NH3**
4. **H2S** (lowest polarity)

### Conclusion
The correct order of polarity for the compounds is:
**HF > H2O > NH3 > H2S**