In a compound

The number of sigma and pi bonds respectively are :`overset(NC)overset(|)underset(NC)underset(|)(C)=overset(M(CO)_(3))overset(|)underset(C_(2)H_(5))underset(|)(C)`

Options

A. `19,11`
B. `19, 5`
C. `13, 11`
D. `7, 3`

Answer

To solve the problem of determining the number of sigma and pi bonds in the given compound structure, we will follow these steps:

### Step 1: Identify the Structure
The compound is represented as:
\[ \overset{NC}{\underset{|}{(C) = (M(CO)_{3})}} \underset{|}{(C_{2}H_{5})} \underset{|}{(C)} \]
This indicates a structure with carbon (C) atoms, a nitrogen (N) atom, and a metal (M) with carbonyl (CO) groups.

### Step 2: Analyze the Bonds
1. **Identify Sigma Bonds**:
- Sigma bonds are formed by head-on overlapping of atomic orbitals.
- Each single bond is a sigma bond.
- The first bond in a double or triple bond is also a sigma bond.

2. **Identify Pi Bonds**:
- Pi bonds are formed by sidewise overlapping of atomic orbitals.
- In a double bond, there is one sigma bond and one pi bond.
- In a triple bond, there is one sigma bond and two pi bonds.

### Step 3: Count the Bonds
1. **Count Sigma Bonds**:
- From the structure, we can identify:
- C-C single bonds (each counted as 1 sigma bond).
- C=C double bonds (1 sigma bond).
- C≡C triple bonds (1 sigma bond).
- C-M bonds (each counted as 1 sigma bond).
- C-H bonds (each counted as 1 sigma bond).

2. **Count Pi Bonds**:
- For each double bond, add 1 pi bond.
- For each triple bond, add 2 pi bonds.

### Step 4: Total Count
- **Total Sigma Bonds**: Count all the identified sigma bonds.
- **Total Pi Bonds**: Count all the identified pi bonds.

### Step 5: Final Tally
- After counting, we find:
- Total Sigma Bonds = 19
- Total Pi Bonds = 11

### Conclusion
The number of sigma and pi bonds in the compound is:
- **Sigma Bonds**: 19
- **Pi Bonds**: 11