The comcept of redistribution of energy in different orbitals of an atom associated with different energies to give new orbitals of equal (or somethimes it may be non-equal) energy oriented in space in definite directions is called hybridization and formed new orbitals are called hybrid orbitals. The bonds formed by such orbitals are called hybrid bonds. The process of mixing of orbitals itself requires some energy. Thus, some additional energy, is needed for the hybridisation (mixing) of atomic orbitals.
Q. Which of the following statement is correct?

Options

A. In `BrF_(3)`, maximum three halogen atoms can lie in same plane
B. In `CH_(2)SF_(2)(CH_(3))_(2)` molecule all hydrogen atoms which bonded to `s-sp^(2)`overlapping, lie in equitorial plane
C. In `OSCl_(4), Cl-S-Cl` equitorial bond angle is greater than `120^(@)`
D. Molecules `IOF_(5) and XeO_(2)F_(4)` have similar shape but have different number of lone pairs in whole molecule

Explanation

To solve the question regarding hybridization and the correctness of the given statements, we will analyze each option step-by-step.

### Step 1: Understand Hybridization
Hybridization is the process of mixing atomic orbitals to form new hybrid orbitals that are degenerate (equal energy) or non-degenerate (unequal energy) and oriented in specific spatial directions. This concept is crucial in predicting the geometry and bonding properties of molecules.

### Step 2: Analyze Each Statement

**Option 1: BF3 has maximum three halogen atoms lying in the same plane.**
- **Analysis:** In BF3, the boron atom is at the center with three fluorine atoms bonded to it. The molecular geometry is trigonal planar, meaning all three fluorine atoms lie in the same plane. Therefore, this statement is **correct**.

**Option 2: In CH2SF2, all the hydrogen atoms which bonded to sp2 overlapping lie in the equatorial plane.**
- **Analysis:** In CH2SF2, sulfur is sp3 hybridized, and the two hydrogen atoms bonded to carbon (which is sp2 hybridized) do lie in the same plane. However, the sulfur's two fluorine atoms will occupy axial positions due to their higher electronegativity. Thus, this statement is **incorrect**.

**Option 3: In OSCl4, the Cl equatorial bond angle is equal to 120 degrees.**
- **Analysis:** In OSCl4, the sulfur atom is bonded to one oxygen atom and four chlorine atoms. The geometry is based on a tetrahedral arrangement around the sulfur atom, and the bond angles are approximately 109.5 degrees, not 120 degrees. Therefore, this statement is **incorrect**.

**Option 4: Molecules of IOF5 and XCO2F4 have similar shape but have different numbers of lone pairs in the whole molecule.**
- **Analysis:** Both IOF5 and XCO2F4 have a similar octahedral shape due to the presence of six bonded atoms (5 fluorine atoms and 1 oxygen in IOF5, and 4 fluorine and 2 oxygen in XCO2F4). However, they do have different numbers of lone pairs. Therefore, this statement is **correct**.

### Conclusion
Based on the analysis:
- **Correct Statements:** Option 1 and Option 4 are correct.
- **Incorrect Statements:** Option 2 and Option 3 are incorrect.

### Final Answer
The correct statements are: **Option 1 and Option 4.**