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Drago suggested an emprical rule which i...

Drago suggested an emprical rule which is compatible with the energetics of hybridization. It will occupy a stereochemically inactive s-orbital, and the bonding will be through p-orbitals and bond angles will be nearly `90^(@)` if the electronegativity of the surrounding atoms is `le2.5`.
Q. In which of the following molecule central atom has higher % s-character in its bond pair:

A

`AsH_(3)`

B

`GeH_(4)`

C

`P_(4)`

D

`H_(2)Se`

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To determine which molecule has a central atom with the highest percentage of s-character in its bond pairs according to Drago's empirical rule, we will analyze the given options step by step. ### Step 1: Understand Drago's Rule Drago's rule states that: 1. The central atom should have at least one lone pair of electrons. 2. The central atom should belong to group 13 to 16 or from the 3rd to 7th period. 3. The electronegativity of the surrounding atoms should be less than or equal to 2.5. 4. If there are four lone pairs, sigma bonds are absent. ### Step 2: Analyze Each Molecule We will analyze the central atom of each molecule provided in the options to determine the percentage of s-character. 1. **Arsenic (As) in Arsenic Compounds (e.g., AsH3)**: - Group: 15 (has 5 valence electrons) - Lone pairs: 1 (3 used for bonding) - Hybridization: None needed according to Drago's rule. - s-character: 33.33% (since it can be considered as having sp3 hybridization if needed). 2. **Germanium (Ge) in GeH4**: - Group: 14 (has 4 valence electrons) - Lone pairs: 0 (all electrons are used for bonding) - Hybridization: sp3 (due to 4 bonds). - s-character: 25%. 3. **Phosphorus (P) in P4**: - Group: 15 (has 5 valence electrons) - Lone pairs: 1 (3 used for bonding with other P atoms) - Hybridization: None needed according to Drago's rule. - s-character: 33.33%. 4. **Selenium (Se) in H2Se**: - Group: 16 (has 6 valence electrons) - Lone pairs: 2 (2 used for bonding with H) - Hybridization: None needed according to Drago's rule. - s-character: 50% (considering it as having sp2 hybridization). ### Step 3: Compare s-Character Now we compare the percentage of s-character in the bond pairs of the central atoms: - As: 33.33% - Ge: 25% - P: 33.33% - Se: 50% ### Conclusion The molecule with the central atom that has the highest percentage of s-character is **H2Se**, where selenium has 50% s-character in its bond pairs. ### Final Answer **H2Se** has the highest percentage of s-character in its bond pair. ---
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Drago suggested an emprical rule which is compatible with the energetics of hybridization. It will occupy a stereochemically inactive s-orbital, and the bonding will be through p-orbitals and bond angles will be nearly 90^(@) if the electronegativity of the surrounding atoms is le2.5 . Q. Correct order of bond angle is :

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . In which of the following option, covalent bond is having maximum s% character ?

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . In which of the following option, covalent bond is having maximum s% character ?

In which of the following the central atom does not use sp^(2) hybrid orbitals in its bonding

In which of the following the central atom use sp^(2) hybrid orbitals in its bonding

In which of the following the central atom does not use sp^3 hybrid orbitals in its bonding

In which of the following molecules, the central atom has one lone pair and three bond pairs of electrons.

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . Select incorrect statement regarding P_(4) molecule.

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . Select incorrect statement regarding P_(4) molecule.

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . The hybridisation of atomic orbitals of central atom "Xe" in XeO_(4), XeO_(2)F_(2) and XeOF_(4) respectively.

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