Select the correct statement(s) regarding `BF_(2)NH_(2)` molecule:

Options

A. FBF bond angle `lt120^(@)`
B. HNH bond angle `gt109^(@)28'`
C. HNH bond angle `lt109^(@)28'`
D. FBF bond angle `gt120^(@)`

Explanation

To analyze the molecule \( BF_2NH_2 \) and select the correct statements regarding it, we will follow these steps:

### Step 1: Determine the Structure of \( BF_2NH_2 \)
- The molecule consists of a boron (B) atom bonded to two fluorine (F) atoms and one amine group (NH2).
- Boron has an atomic number of 5 and an electronic configuration of \( 1s^2 2s^2 2p^1 \). It can form three bonds but is electron-deficient.
- Nitrogen has an atomic number of 7 with an electronic configuration of \( 1s^2 2s^2 2p^3 \), allowing it to form three bonds (two with hydrogen and one with boron).

**Hint:** Identify the central atom and its bonding partners to understand the molecular structure.

### Step 2: Analyze Hybridization
- Boron in \( BF_2NH_2 \) is sp² hybridized because it forms three sigma bonds (two with fluorine and one with nitrogen).
- Nitrogen is initially sp³ hybridized due to its lone pair but becomes sp² hybridized after donating its lone pair to boron.

**Hint:** Check the number of bonds and lone pairs to determine hybridization.

### Step 3: Determine Bond Angles
- For sp² hybridization, the ideal bond angle is 120 degrees. Thus, the bond angle between the fluorine atoms (F-B-F) is expected to be around 120 degrees.
- However, due to the presence of the pi bond and the electron density from the fluorine atoms, the F-B-F bond angle will be slightly less than 120 degrees due to repulsion from the pi electrons.
- The bond angle between nitrogen and hydrogen (H-N-H) will be greater than 109.28 degrees because nitrogen is now sp² hybridized.

**Hint:** Use the hybridization type to predict bond angles.

### Step 4: Conclusion on Bond Angles
- The bond angle \( \angle FBF \) is less than 120 degrees.
- The bond angle \( \angle HNH \) is greater than 109.28 degrees.

### Final Statements
Based on the analysis, the correct statements regarding \( BF_2NH_2 \) are:
1. The \( FBF \) bond angle is less than 120 degrees.
2. The \( HNH \) bond angle is greater than 109.28 degrees.