In the structure of `H_(2)CSF_(4)`, which of the following statement is/are correct?

Options

A. Two `C-H` bonds are in the same plane of axial `S-F` bonds
B. Two `C-H` bonds are in the same plane of equitorial `S-F` bonds
C. Total six atoms are in the plane
D. Equitorial `S-F` plane is perpendicular to the nodal plane of `pi-` bonds

Explanation

To determine which statements about the structure of \( H_2CSF_4 \) are correct, we first need to analyze the molecular structure and bonding of the compound. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Central Atom and Its Hybridization
- The central atom in \( H_2CSF_4 \) is sulfur (S).
- Sulfur has an electronic configuration of \( [Ne] 3s^2 3p^4 \).
- To form bonds with four fluorine atoms and two hydrogen atoms, sulfur undergoes hybridization.

**Hint:** Consider the number of bonds sulfur needs to form and how this relates to its electron configuration.

### Step 2: Determine the Hybridization
- Sulfur can promote one of its 3s electrons to the 3d orbital to accommodate the bonding requirements.
- This results in \( sp^3d^2 \) hybridization, allowing sulfur to form a total of six bonds (four with fluorine and two with hydrogen).

**Hint:** Think about how many orbitals are involved in bonding and how they can be hybridized.

### Step 3: Analyze the Molecular Geometry
- The molecular geometry of \( H_2CSF_4 \) is octahedral due to the \( sp^3d^2 \) hybridization.
- The two hydrogen atoms will occupy positions in the equatorial plane, while the four fluorine atoms will occupy the axial positions.

**Hint:** Visualize the arrangement of atoms in three-dimensional space to understand the geometry.

### Step 4: Evaluate the Statements
1. **Statement A:** "Two CH bonds are in the same plane as the axial SF bonds."
- This statement is incorrect. The CH bonds are in the equatorial plane, while the SF bonds are axial.

2. **Statement B:** "Total six atoms are in the same plane."
- This statement is correct. All six atoms (two H and four F) can be arranged in a way that they lie in the same plane.

3. **Statement C:** "Equatorial SF bonds are perpendicular to the nodal plane of the pi bond."
- This statement is correct. The SF bonds are indeed perpendicular to the nodal plane of the pi bond formed.

4. **Statement D:** "The CH bonds are perpendicular to the equatorial SF bonds."
- This statement is correct. The CH bonds are positioned perpendicular to the equatorial SF bonds.

### Conclusion
Based on the analysis:
- Statements B, C, and D are correct.
- Statement A is incorrect.

### Final Answer
The correct statements regarding the structure of \( H_2CSF_4 \) are B, C, and D.