Total number of species which has/ have symmetrical electronic distribution in their HOMO and also paramagnetic.
`N_(2)^(+), O_(2)^(2-), C_(2), O_(2), B_(2), C_(2)^(2-), N_(2)^(2-)`.

Explanation

To solve the question regarding the total number of species that have symmetrical electronic distribution in their highest occupied molecular orbital (HOMO) and are also paramagnetic, we will analyze each given species step by step.

### Step 1: Understand the Terms
- **Symmetrical Electronic Distribution**: This means that the electrons in the HOMO are distributed evenly across the available orbitals. For example, if there are two electrons in two degenerate orbitals, they should occupy different orbitals (one in each) to maintain symmetry.
- **Paramagnetic**: A species is paramagnetic if it has unpaired electrons in its electronic configuration.

### Step 2: Analyze Each Species
1. **N₂⁺**:
- Total electrons: 13 (N₂ has 14 electrons; removing one gives 13)
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) σ2p_z¹ (1 unpaired electron)
- HOMO: σ2p_z (1 unpaired electron)
- **Conclusion**: Symmetrical and paramagnetic.

2. **O₂²⁻**:
- Total electrons: 18 (O₂ has 16 electrons; adding two gives 18)
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) σ2p_z² (2) π2p_x² (2) π2p_y² (2)
- HOMO: π2p_x² and π2p_y² (all paired)
- **Conclusion**: Symmetrical but not paramagnetic.

3. **C₂**:
- Total electrons: 12
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) π2p_x² (2) π2p_y² (2)
- HOMO: π2p_x² and π2p_y² (all paired)
- **Conclusion**: Symmetrical but not paramagnetic.

4. **O₂**:
- Total electrons: 16
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) σ2p_z² (2) π2p_x¹ (1) π2p_y¹ (1)
- HOMO: π2p_x¹ and π2p_y¹ (2 unpaired electrons)
- **Conclusion**: Symmetrical and paramagnetic.

5. **B₂**:
- Total electrons: 10
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) π2p_x¹ (1) π2p_y¹ (1)
- HOMO: π2p_x¹ and π2p_y¹ (2 unpaired electrons)
- **Conclusion**: Symmetrical and paramagnetic.

6. **C₂²⁻**:
- Total electrons: 14
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) π2p_x² (2) π2p_y² (2)
- HOMO: π2p_x² and π2p_y² (all paired)
- **Conclusion**: Symmetrical but not paramagnetic.

7. **N₂²⁻**:
- Total electrons: 16 (N₂ has 14 electrons; adding two gives 16)
- Electronic configuration: σ1s² σ*1s² σ2s² σ*2s² (4) π2p_x² (2) π2p_y² (2) σ2p_z² (2)
- HOMO: σ2p_z² (all paired)
- **Conclusion**: Symmetrical but not paramagnetic.

### Step 3: Count the Paramagnetic Species
From the analysis:
- Paramagnetic species: **N₂⁺, O₂, B₂, N₂²⁻**
- Total count: **4 species**

### Final Answer
The total number of species which have symmetrical electronic distribution in their HOMO and are also paramagnetic is **4**.

---