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Number of hybrid orbital C atoms which h...

Number of hybrid orbital C atoms which have 33% p-character in `C(CN)_(4)`.

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To determine the number of hybrid orbitals of carbon atoms that have 33% p-character in the compound C(CN)₄, we can follow these steps: ### Step 1: Identify the Hybridization of Carbon Atoms - In the compound C(CN)₄, we have one central carbon atom (C) bonded to four cyanide groups (CN). - Each CN group has a carbon atom that is involved in a triple bond with nitrogen. ### Step 2: Analyze the Hybridization of the Central Carbon Atom - The central carbon atom is bonded to four cyanide groups. - The steric number (SN) for the central carbon is calculated as follows: - Number of sigma bonds: 4 (one from each CN bond) - Number of lone pairs: 0 - Therefore, SN = 4 + 0 = 4. - A steric number of 4 indicates that the hybridization of the central carbon atom is sp³. ### Step 3: Analyze the Hybridization of the Carbon Atoms in CN - Each carbon atom in the CN group is involved in a triple bond with nitrogen. - The steric number for each carbon in CN is: - Number of sigma bonds: 1 (from the CN bond) - Number of lone pairs: 0 - Therefore, SN = 1 + 0 = 1. - A steric number of 1 indicates that the hybridization of each carbon atom in CN is sp. ### Step 4: Determine the p-Character of Each Hybridization - The p-character for different hybridizations is as follows: - sp hybridization: 50% s and 50% p - sp² hybridization: 33% s and 67% p - sp³ hybridization: 25% s and 75% p - Since we are looking for carbon atoms with 33% p-character, we note that: - sp hybridization has 50% p-character. - sp² hybridization has 67% p-character. - sp³ hybridization has 75% p-character. ### Step 5: Conclusion - In the compound C(CN)₄, we have: - The central carbon atom is sp³ hybridized (75% p-character). - The carbon atoms in the cyanide groups are sp hybridized (50% p-character). - Therefore, there are no carbon atoms with 33% p-character in C(CN)₄. ### Final Answer - The number of hybrid orbitals of carbon atoms which have 33% p-character in C(CN)₄ is **0**. ---
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