There are some species given below. (i)`O_(2)^(+)` (ii)`CO` (iii)`B_(2)` (iv)`O_(2)^(-)` (v)`NO^(+)` (vi)`He_(2)^(+)` (vii)`C_(2)^(2+)` (vii)` CN^(-)` (ix)` N_(2)^(-)`
total number of species which have fractional bond order.

Explanation

To determine the total number of species with fractional bond orders from the given list, we will calculate the bond order for each species step by step.

### Step 1: Calculate the bond order for each species.

1. **Species: O₂⁺**
- Total electrons = 15 (Oxygen has 8 electrons, so O₂ has 16, and the positive charge means we remove 1 electron).
- Electron configuration:
- σ1s² σ*1s² σ2s² σ*2s² σ2p_z² π2p_x² π2p_y² π*2p_x¹
- Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2
- Bonding = 10, Antibonding = 5
- Bond order = (10 - 5) / 2 = 2.5 (Fractional)

2. **Species: CO**
- Total electrons = 14 (C has 6, O has 8).
- Bond order = 3 (C≡O triple bond, no fractional).

3. **Species: B₂**
- Total electrons = 10 (Boron has 5 electrons).
- Bond order = 1 (B–B single bond, no fractional).

4. **Species: O₂⁻**
- Total electrons = 17 (O₂ has 16, and the negative charge means we add 1 electron).
- Bond order = (10 - 7) / 2 = 1.5 (Fractional).

5. **Species: NO⁺**
- Total electrons = 14 (N has 7, O has 8, minus 1 for the positive charge).
- Bond order = 3 (N=O double bond, no fractional).

6. **Species: He₂⁺**
- Total electrons = 2 (He has 2 electrons, and we remove 1 for the positive charge).
- Bond order = (1 - 0) / 2 = 0.5 (Fractional).

7. **Species: C₂²⁺**
- Total electrons = 10 (C has 6, and we remove 2 for the positive charge).
- Bond order = 1 (C–C single bond, no fractional).

8. **Species: CN⁻**
- Total electrons = 14 (C has 6, N has 7, and we add 1 for the negative charge).
- Bond order = 3 (C≡N triple bond, no fractional).

9. **Species: N₂⁻**
- Total electrons = 15 (N₂ has 14, and we add 1 for the negative charge).
- Bond order = 2.5 (Fractional).

### Step 2: Count the species with fractional bond orders.
- Species with fractional bond orders:
1. O₂⁺ (2.5)
2. O₂⁻ (1.5)
3. He₂⁺ (0.5)
4. N₂⁻ (2.5)

### Conclusion:
The total number of species that have fractional bond orders is **4**.

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