In the extraction of copper from copper pyrites, iron is removed as :

Options

A. `FeSO_(4)`
B. `FeSiO_(3)`
C. `Fe_(3)O_(4)`
D. `Fe_(2)O_(3)`

Answer

To solve the question regarding the removal of iron during the extraction of copper from copper pyrites, we can follow these steps:

### Step 1: Understand the process of extraction
Copper is primarily extracted from copper pyrites (CuFeS₂) through a series of processes including roasting and smelting. During these processes, iron is also present and needs to be removed.

**Hint:** Familiarize yourself with the overall extraction process of copper from its ores, particularly the role of roasting and smelting.

### Step 2: Identify the role of flux
In metallurgy, a flux is a substance that is added to combine with impurities and form a slag, which can be easily removed. In the case of copper extraction from copper pyrites, silica (SiO₂) is commonly used as a flux.

**Hint:** Remember that fluxes are used to help remove impurities by forming compounds that can be separated from the desired metal.

### Step 3: Determine the reaction between iron oxide and silica
When copper pyrites are roasted, iron present in the ore is converted to iron oxide (FeO or Fe₂O₃). When silica is added, it reacts with iron oxide to form iron silicate.

**Hint:** Look for the chemical reactions that occur during the roasting of copper pyrites and how they relate to the removal of iron.

### Step 4: Identify the product formed
The reaction between iron oxide and silica can be represented as:
\[ \text{FeO} + \text{SiO}_2 \rightarrow \text{FeSiO}_3 \]
This compound, FeSiO₃, is known as slag and is the form in which iron is removed during the extraction process.

**Hint:** Focus on the products of the reaction between iron oxides and silica to identify the correct slag formed.

### Step 5: Conclusion
Based on the above steps, we conclude that in the extraction of copper from copper pyrites, iron is removed as slag in the form of FeSiO₃.

**Final Answer:** The correct option is **FeSiO₃** (option 2).