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Let f (x) be a polynomial satisfying lim...

Let `f (x)` be a polynomial satisfying `lim _(x to oo) (x ^(4) f (x))/( x ^(8) +1)=3`
`f (2) =5, f(3) =10, f (-1)=2, f (-6)=37`
The number of points of discontinuity of discontinuity of `f (x)= (1)/(x ^(2)+1 -f (x)) ` in` [(-15)/(2), (5)/(2)]` equals:

A

4

B

3

C

1

D

0

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The correct Answer is:
To solve the problem, we need to find the number of points of discontinuity of the function \( g(x) = \frac{1}{x^2 + 1 - f(x)} \) in the interval \([-15/2, 5/2]\). ### Step 1: Determine the polynomial \( f(x) \) Given the limit: \[ \lim_{x \to \infty} \frac{x^4 f(x)}{x^8 + 1} = 3 \] This implies that the degree of \( f(x) \) must be 4, since the degree of the numerator (which is \( x^4 f(x) \)) must equal the degree of the denominator (which is 8). Therefore, we can express \( f(x) \) as: \[ f(x) = ax^4 + bx^3 + cx^2 + dx + e \] where \( a \) is a constant that we will determine. ### Step 2: Find the leading coefficient \( a \) From the limit, we have: \[ \lim_{x \to \infty} \frac{x^4 f(x)}{x^8} = \lim_{x \to \infty} \frac{f(x)}{x^4} = 3 \implies a = 3 \] Thus, we can write: \[ f(x) = 3x^4 + bx^3 + cx^2 + dx + e \] ### Step 3: Use the given values to find coefficients We have the following values: - \( f(2) = 5 \) - \( f(3) = 10 \) - \( f(-1) = 2 \) - \( f(-6) = 37 \) Substituting \( x = 2 \): \[ f(2) = 3(2^4) + b(2^3) + c(2^2) + d(2) + e = 48 + 8b + 4c + 2d + e = 5 \tag{1} \] Substituting \( x = 3 \): \[ f(3) = 3(3^4) + b(3^3) + c(3^2) + d(3) + e = 243 + 27b + 9c + 3d + e = 10 \tag{2} \] Substituting \( x = -1 \): \[ f(-1) = 3(-1^4) + b(-1^3) + c(-1^2) + d(-1) + e = 3 - b + c - d + e = 2 \tag{3} \] Substituting \( x = -6 \): \[ f(-6) = 3(-6^4) + b(-6^3) + c(-6^2) + d(-6) + e = 3888 - 216b + 36c - 6d + e = 37 \tag{4} \] ### Step 4: Solve the system of equations We now have a system of equations (1), (2), (3), and (4). We can solve these equations to find \( b, c, d, e \). ### Step 5: Identify points of discontinuity of \( g(x) \) The function \( g(x) \) is discontinuous where the denominator \( x^2 + 1 - f(x) = 0 \). We need to find the roots of: \[ x^2 + 1 - f(x) = 0 \] This will give us the points of discontinuity. ### Step 6: Check the interval \([-15/2, 5/2]\) We need to check how many of these roots fall within the interval \([-15/2, 5/2]\). ### Conclusion After solving the equations and finding the roots of \( g(x) \), we can count how many of them lie within the specified interval.
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VK JAISWAL ENGLISH-CONTINUITY, DIFFERENTIABILITY AND DIFFERENTIATION-EXERCISE (COMPREHENSION TYPE PROBLEMS)
  1. Consider a function f (x) in [0,2pi] defined as : f(x)=[{:([sinx]+ ...

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  2. Let f (x)= {{:(x [x] , 0 le x lt 2),( (x-1), 2 le x le 3):} where [x]=...

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  3. Let f (x)= {{:(x [x] , 0 le x lt 2),( (x-1), 2 le x le 3):} where [x]=...

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  4. Let f (x)= {{:(x [x] , 0 le x lt 2),( (x-1), 2 le x le 3):} where [x]=...

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  5. Let f :R to R be a continous and differentiable function such that f (...

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  6. Let f :R to R be a continous and differentiable function such that f (...

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  7. Let f :R to R be a continous and differentiable function such that f (...

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  9. Let f (x) (cos ^(2) x)/(1+ cos +cos ^(2)x )and g (x) lamda tan x+1(1-l...

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  10. Let f and g be two differentiable functins such that: f (x)=g '(1) s...

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  11. Let f and g be two differentiable functins such that: f (x)=g '(1) s...

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  12. Let f and g be two differentiable functins such that: f (x)=g '(1) s...

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  13. Suppose a function f(x) satisfies the following conditions f (x+y) =...

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  14. Suppose a function f(x) satisfies the following conditions f (x+y) =...

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  15. Let f (x) be a polynomial satisfying lim (x to oo) (x ^(4) f (x))/( x ...

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  16. Let f (x) be a polynomial satisfying lim (x to oo) (x ^(4) f (x))/( x ...

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  17. Consider f (x) = x ^(ln x), and g (x) = e ^(2) x. Let alpha and beta b...

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  18. Consider f (x) = x ^(ln x), and g (x) = e ^(2) x. Let alpha and beta b...

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  19. Let f (n) x+ f (n) (y ) = (x ^(n)+y ^(n))/(x ^(n) y ^(n))AA x, y in R-...

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  20. Let f (n) x+ f (n) (y ) = (x ^(n)+y ^(n))/(x ^(n) y ^(n))AA x, y in R-...

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