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The function f(x) = sin^3 x-m sin x is d...

The function `f(x) = sin^3 x-m sin x` is defined on open interval `(-pi/2,pi/2)` and if assumes only 1 maximum value and only 1 minimum value on this interval. Then, which one of the must be correct? (a) `0lt m lt 3` (b) `-3 lt m lt 0` (c) `m gt 3` (d) `m lt -3`

A

`0lt m lt 3`

B

`-3 lt m lt 0`

C

`m gt 3`

D

`m lt -3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = \sin^3 x - m \sin x \) and determine the conditions under which it has only one maximum and one minimum value in the interval \( (-\frac{\pi}{2}, \frac{\pi}{2}) \). ### Step 1: Differentiate the function We start by finding the derivative of the function \( f(x) \): \[ f'(x) = \frac{d}{dx}(\sin^3 x - m \sin x) \] Using the chain rule and product rule, we get: \[ f'(x) = 3 \sin^2 x \cos x - m \cos x \] ### Step 2: Set the derivative to zero To find the critical points, we set the derivative equal to zero: \[ f'(x) = 0 \implies 3 \sin^2 x \cos x - m \cos x = 0 \] Factoring out \( \cos x \): \[ \cos x (3 \sin^2 x - m) = 0 \] This gives us two cases: 1. \( \cos x = 0 \) 2. \( 3 \sin^2 x - m = 0 \) ### Step 3: Analyze the first case The first case, \( \cos x = 0 \), occurs at \( x = \pm \frac{\pi}{2} \). However, these points are not included in the open interval \( (-\frac{\pi}{2}, \frac{\pi}{2}) \). Therefore, we discard this case. ### Step 4: Analyze the second case For the second case, we solve: \[ 3 \sin^2 x - m = 0 \implies \sin^2 x = \frac{m}{3} \] ### Step 5: Determine the range of \( \sin^2 x \) Since \( x \) is in the interval \( (-\frac{\pi}{2}, \frac{\pi}{2}) \), the range of \( \sin x \) is \( (-1, 1) \). Therefore, \( \sin^2 x \) will be in the range \( (0, 1) \). This means: \[ 0 < \sin^2 x < 1 \] Substituting \( \sin^2 x = \frac{m}{3} \): \[ 0 < \frac{m}{3} < 1 \] ### Step 6: Solve the inequalities Multiplying through by 3 gives: \[ 0 < m < 3 \] ### Conclusion Thus, the value of \( m \) must satisfy \( 0 < m < 3 \). The correct option that corresponds to this condition is: **(a) \( 0 < m < 3 \)**
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VK JAISWAL ENGLISH-APPLICATION OF DERIVATIVES -EXERCISE (SUBJECTIVE TYPE PROBLEMS)
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