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If 3/(4!)+4/(5!)+5/(6!)+.....+50 term=1/...

If `3/(4!)+4/(5!)+5/(6!)+.....+50 term=1/(3!)-1/((k+3)!)`, then sum of coefficients in the expansion `(1+2x_1+3x_2+.....+100x_(100))^k` is:

A

`(5050)^(49)`

B

`(5050)^(51)`

C

`(5050)^(52)`

D

`(5050)^(50)`

Text Solution

Verified by Experts

The correct Answer is:
D
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