Home
Class 12
MATHS
""^(26)C(0)+""^(26)C(1)+""^(26)C(2)+…..+...

`""^(26)C_(0)+""^(26)C_(1)+""^(26)C_(2)+…..+""^(26)C_(13)` is equal to :

A

`2^(25)-(1)/(2)*""^(26)C_(13)`

B

`2^(25)+(1)/(2)*""^(26)C_(13)`

C

`2^(13)`

D

`2^(26)+(1)/(2)*""^(26)C_(13)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • BIONMIAL THEOREM

    VK JAISWAL ENGLISH|Exercise Exercise-2 : One or More than One Answer is/are Correct|9 Videos
  • BIONMIAL THEOREM

    VK JAISWAL ENGLISH|Exercise Exercise-3 : Matching Type Problems|2 Videos
  • AREA UNDER CURVES

    VK JAISWAL ENGLISH|Exercise EXERCISE (SUBJECTIVE TYPE PROBLEMS)|8 Videos
  • CIRCLE

    VK JAISWAL ENGLISH|Exercise Exercise - 5 : Subjective Type Problems|12 Videos

Similar Questions

Explore conceptually related problems

Prove that : ""^(25)C_(10)+""^(24)C_(10)+……..+""^(10)C_(10)=""^(26)C_(11)

Two packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination is a. ^(52) C_(26). 2^(26) b. ^104 C_(26) c. ^(52)C_(26) d. none of these

If the value of the definite integral int_0^1 "^(207)C_7x^(200)(1-x)^7dx is equal to 1/k ,w h e r ek in N , then the value of k/(26) is____

For the reaction PCl_(3)(g)+Cl_(2)(g)rarrPCl_(5)(g),K_(c) is 26 at 250^(@)C . K_(p) at the same temperature is (R=8.314JK^(-1)mol^(-1))

Evaluate C(31,26)-C(30,26)

The area of a parallelogram whose diagonals are 3hati + 4 hatj,hati + hatj+ hatk is a) sqrt(26) b) sqrt(26)/(2) c) sqrt(26)/(3) d) none of these

A compound has the empirical formula C_(10)H_(8)Fe . A solution of 0.26 g of the compound in 11.2 g of benzene ( C_(6)H_(6) )boils at 80.26^(@)C . The boiling point of benzene is 80.10^(@)C , the K_(b) is 2.53^(@)C /molal. What is the molecules formula of the compound? (a) C_(30)H_(24)Fe_(3) (b) C_(10)H_(8)Fe (c) C_(5)H_(4)Fe (d) C_(20)H_(16)Fe_(2)

a) 26 (b) 52 (c) 338 (d) 13

A well with inner diameter 8 m is dug 14 m deep. Earth taken out of its has been evenly spread all around it to a width of 3 m to form an embankment. The height of the embankment will be 4(26)/(33)m (b) 5(26)/(33)c m (c) 6(26)/(33)c m (d) 7(26)/(33)c m

If int x^(26).(x-1)^(17).(5x-3)dx=(x^(27).(x-1)^(18))/(k)+C where C is a constant of integration, then the value of k is equal to

VK JAISWAL ENGLISH-BIONMIAL THEOREM-Exercise-4 : Subjective Type Problems
  1. ""^(26)C(0)+""^(26)C(1)+""^(26)C(2)+…..+""^(26)C(13) is equal to :

    Text Solution

    |

  2. The sum of series 3*""^(2007)C(0)-8*""^(2007)C(1)+13*""^(2007)C(2)-18...

    Text Solution

    |

  3. In the polynomial (x-1)(x^(2)-2)(x^(3)-3)…(x^(11)-11), the coefficient...

    Text Solution

    |

  4. If sum(r=0)^(2n)ar(x-2)^r=sum(r=0)^(2n)br(x-3)^ra n dak=1 for all kgeq...

    Text Solution

    |

  5. If 3^(101)-2^(100) is divided by 11, the remainder is

    Text Solution

    |

  6. Find the hundred's digit in the co-efficient of x^(17) in the expansio...

    Text Solution

    |

  7. Let x=(3sqrt(6)+7)^(89). If {x} denotes the fractional part of 'x' the...

    Text Solution

    |

  8. Let n in N, S(n)=sum(r=0)^(3n)(""^(3n)C(r )) and T(n)=sum(r=0)^(n)(""^...

    Text Solution

    |

  9. Find the sum of possible real values of x for which the sixth term of ...

    Text Solution

    |

  10. Let q be a positive with q le 50. If the sum ""^(98)C(30)+2" "^(97)C...

    Text Solution

    |

  11. The remainder when (sum(k=1)^(5) ""^(20)C(2k-1))^(6) is divided by 11,...

    Text Solution

    |

  12. Let a=3^(1/(223))+1 and for all geq3,l e tf(n)=^n C0dota^(n-1)-^n C1do...

    Text Solution

    |

  13. In the polynomial (x-1)(x^(2)-2)(x^(3)-3)…(x^(11)-11), the coefficient...

    Text Solution

    |

  14. Let the sum of all divisiors of the form 2^(p)*3^(q) (with p, q posit...

    Text Solution

    |

  15. about to only mathematics

    Text Solution

    |

  16. Let 1+sum(r=1)^(10)(3^r.^(10)Cr+r.^(10)Cr)=2^(10)(alpha. 4^5+beta) whe...

    Text Solution

    |

  17. Let S(n)=""^(n)C(0)""^(n)C(1)+""^(n)C(1)""^(n)C(2)+…..+""^(n)C(n-1)""^...

    Text Solution

    |