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If sum(r=0)^(2n)ar(x-2)^r=sum(r=0)^(2n)b...

If `sum_(r=0)^(2n)a_r(x-2)^r=sum_(r=0)^(2n)b_r(x-3)^ra n da_k=1` for all `kgeqn ,` then show that `b_n=^(2n+1)C_(n+1)` .

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