Answer
Step by step text solution for A consignment of 15 record players contain 4 defectives. The record players are selected at random, one by one and examined. The one examined is not put back. Then : Find the Probability that 9^(th) one examined is the last defective is (8)/(195). by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.
|
Topper's Solved these Questions
PROBABILITY
VK JAISWAL ENGLISH|Exercise Exercise-3 : Comprehension Type Problems|12 VideosView PlaylistPROBABILITY
VK JAISWAL ENGLISH|Exercise Exercise-4 : Matching Type Problems|1 VideosView PlaylistPROBABILITY
VK JAISWAL ENGLISH|Exercise Exercise -5 : Subjective Type problems|11 VideosView PlaylistPERMUTATION AND COMBINATIONS
VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|13 VideosView PlaylistQUADRATIC EQUATIONS
VK JAISWAL ENGLISH|Exercise EXERCISE (SUBJECTIVE TYPE PROBLEMS)|43 VideosView Playlist
Similar Questions
Explore conceptually related problems
VK JAISWAL ENGLISH-PROBABILITY -Exercise-2 : One or More than One Answer is/are Correct
- A consignment of 15 record players contain 4 defectives. The record p...
04:31
|
Playing Now - If A1,A2,A3,........A1006 be independent events such that P(A)=1/(2i)(...
08:34
|
Play - A bag contains four tickets marked with numbers 112,121,211, and 222. ...
02:10
|
Play - For two events A and B, let P(A) = 3/5, P(B) = 2/3, then which of the ...
10:31
|
Play