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A square OABC is formed by line pairs x...

A square OABC is formed by line pairs `xy=0 and xy+1=x+y` where 'O' is the origin. A circle with centre `C_(1)` inside the square is drawn to touch the line pair `xy=0` and another circle with centre `C_(2)` and radius twice that of `C_(1)`, is drawn to touch the circle `C_(1)` and the other line pair. the radius of the circle with centre `C_(1)` is :

A

`(sqrt(2))/(sqrt(3)(sqrt(2)+1))`

B

`(2sqrt(2))/(3(sqrt(2)+1))`

C

`(sqrt(2))/(3(sqrt(2)+1))`

D

`(sqrt(2)+1)/(3sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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