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The maximum value of sin(x+pi/5)+cos(x+p...

The maximum value of `sin(x+pi/5)+cos(x+pi/5),` where `x in (0, pi/2),` is attained at

A

`(pi)/(12)`

B

`(pi)/(6)`

C

`(pi)/(3)`

D

`(pi)/(20)`

Text Solution

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The correct Answer is:
To find the maximum value of the function \( \sin(x + \frac{\pi}{5}) + \cos(x + \frac{\pi}{5}) \) for \( x \) in the interval \( (0, \frac{\pi}{2}) \), we can follow these steps: ### Step 1: Define the Function Let \( \theta = x + \frac{\pi}{5} \). Then, we can rewrite the function as: \[ f(\theta) = \sin(\theta) + \cos(\theta) \] ### Step 2: Differentiate the Function To find the maximum value, we differentiate \( f(\theta) \) with respect to \( \theta \): \[ f'(\theta) = \cos(\theta) - \sin(\theta) \] ### Step 3: Set the Derivative to Zero To find the critical points, we set the derivative equal to zero: \[ \cos(\theta) - \sin(\theta) = 0 \] This implies: \[ \cos(\theta) = \sin(\theta) \] ### Step 4: Solve for \( \theta \) From \( \cos(\theta) = \sin(\theta) \), we can conclude that: \[ \tan(\theta) = 1 \] This occurs at: \[ \theta = \frac{\pi}{4} \] ### Step 5: Relate \( \theta \) Back to \( x \) Recall that \( \theta = x + \frac{\pi}{5} \). Therefore, we set: \[ x + \frac{\pi}{5} = \frac{\pi}{4} \] ### Step 6: Solve for \( x \) Now, we solve for \( x \): \[ x = \frac{\pi}{4} - \frac{\pi}{5} \] To simplify this, we find a common denominator: \[ x = \frac{5\pi}{20} - \frac{4\pi}{20} = \frac{\pi}{20} \] ### Conclusion Thus, the maximum value of \( \sin(x + \frac{\pi}{5}) + \cos(x + \frac{\pi}{5}) \) is attained at: \[ \boxed{\frac{\pi}{20}} \]
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