Home
Class 11
PHYSICS
Plot the line 2x-3y=12....

Plot the line `2x-3y=12`.

Text Solution

AI Generated Solution

To plot the line given by the equation \(2x - 3y = 12\), we can follow these steps: ### Step 1: Find the x-intercept To find the x-intercept, we set \(y = 0\) in the equation. \[ 2x - 3(0) = 12 \implies 2x = 12 \implies x = \frac{12}{2} = 6 \] ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • BASIC MATHEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|9 Videos
  • BASIC MATHEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 2.1|2 Videos
  • ARCHIVES 2 VOLUME 6

    CENGAGE PHYSICS ENGLISH|Exercise Integer|4 Videos
  • CALORIMETRY

    CENGAGE PHYSICS ENGLISH|Exercise Solved Example|13 Videos

Similar Questions

Explore conceptually related problems

Plot the line -3x-5y=15 .

Find the equation of a line, passes through (-1,2) and perependicular to the line 2x+3y=1 .

Knowledge Check

  • Equation of line mid-parallel to the lines 3x+4y=12 and 3x+4y=2 is

    A
    `4x+3y=7`
    B
    `3x+4y+7=0`
    C
    `3x+4y=7`
    D
    `3x+4y=0`
  • Similar Questions

    Explore conceptually related problems

    The equation of the diameter of the circle 3(x^(2)+y^(2))-2x+6y-9=0 which is perpendicular to the line 2x+3y=12 is

    The distance of the point (1,2) from the line 2x-3y-4=0 in the direction of the line x+y=1 , is

    Express y in terms of x in the equation 2x-3y=12. Find the points whether the point (3,3) is on the line represented by the equation 3x+y-12=0

    Find the equation of the straight line which passes through the point of intersection of lines 3x-4y-7=0 and 12x-5y-13=0 and is perpendicular to the line 2x-3y+5=0

    Prove that the lines 2x+3y=19 and 2x+3y+7=0 are equidistant from the line 2x+3y=6 .

    Find the points on y -axis whose perpendicular distance from the line 4x-3y-12=0 is 3.

    Find the points on y- ais whose perpendicular distance from the line 4x-3y-12=0 is 3.