Calculate the area enclosed under the curve `f(x)=x^2` between the limits `x=2` and `x=3` (figure)

Explanation

`underset2overset3intf(x)dx=underset2overset3intx^2dx`
`=(x^(3))/(3)|_2^3`
`=((3)^3)/(3)-(2)^3/3=19/3=6.333`