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Find (dy)/(dx), when x=a(theta+sintheta)...

Find `(dy)/(dx),` when `x=a(theta+sintheta)a n dy=a(1-costheta)`

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`x=a(theta+sintheta)`
`implies (dx)/(d theta)=a(1+costheta)` (1)
`y=a(1-cos theta)implies(dy)/(d theta)=a(0-(-sin theta))=a sin theta` (2)
Dividing (ii) and (i) `(dy//d theta)/(dx//d theta)=(dy)/(dx)=(sin theta)/(1+cos theta)=tan( theta//2)`
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