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A metallic disc is being heated. Its are...

A metallic disc is being heated. Its area A(in `m^2`) at any time t(in second) is given by `A=5t^2+4t+8`. Calculate the rate of increase in area at `t=3s`.

Text Solution

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`A=5t^2+4t+8`
Rate of inc. of area: `(dA)/(dt)=10t+4`
`((dA)/(dt))_(t=3s)=10xx3+4=34ms^-2`
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