The acceleration of a particle is given by `a=t^3-3t^2+5`, where a is in `ms^-2` and t is in second. At `t=1s`, the displacement and velocity are `8.30m` and `6.25ms^-1`, respectively. Calculate the displacement and velocity at `t=2s`.

Explanation

To solve the problem step-by-step, we will first find the velocity function by integrating the acceleration function, and then we will find the displacement function by integrating the velocity function. Finally, we will evaluate both functions at \( t = 2 \) seconds.

### Step 1: Given Information
The acceleration of the particle is given by:
\[ a(t) = t^3 - 3t^2 + 5 \]
At \( t = 1 \) second, the displacement \( x(1) = 8.30 \, \text{m} \) and the velocity \( v(1) = 6.25 \, \text{m/s} \).
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