Two forces of unequal magnitude simultaneously act on a particle making an angle `theta (=120^(@))` with each other.If one of them is reversed ,the accelaration of the particle is become `sqrt(3)` times. Calculate the ratio of the magnitude of the forces.

Explanation

To solve the problem, we need to find the ratio of the magnitudes of two forces \( F_1 \) and \( F_2 \) acting on a particle at an angle of \( \theta = 120^\circ \). When one of the forces is reversed, the acceleration of the particle becomes \( \sqrt{3} \) times the original acceleration.

### Step-by-Step Solution:

1. **Identify the Forces and Angle**:
Let \( F_1 \) and \( F_2 \) be the magnitudes of the two forces acting on the particle. The angle between them is \( \theta = 120^\circ \).

2. **Calculate the Resultant Force Before Reversal**:
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