Home
Class 11
PHYSICS
A body is projected upwards with a veloc...

A body is projected upwards with a velocity `u`. It passes through a certain point above the grond after `t_(1)`, Find the time after which the body posses thoruth the same point during the journey.

Text Solution

AI Generated Solution

To solve the problem of finding the time after which a body projected upwards with an initial velocity \( u \) passes through the same point during its journey, we can follow these steps: ### Step 1: Understand the Motion When the body is projected upwards, it will rise to a maximum height and then fall back down. The point where it passes through at time \( t_1 \) is at a height \( h \). We need to find the time \( t_2 \) when it passes through the same height \( h \) again. ### Step 2: Use the Equation of Motion We can use the second equation of motion: \[ ...
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|9 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.1|17 Videos

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

  • KINEMATICS-2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise Integer|9 Videos

Similar Questions

Explore conceptually related problems

A body is projected upwards with a velocity u . It passes through a certain point above the ground after t_(1) , Find the time after which the body passes through the same point during the journey.

A body is projected vertically upward with an initial velocity u. If acceleration due to gravity is g, find the time for which it remains in air.

A body is projected up with velocity u. It reaches a point in its path at times t_1 and t_2 seconds from the time of projection. Then (t_1+t_2) is

A body is projected up with a velocity 50 "ms"^(-1) after one second if accelaration due to gravity disappears then body

A body is projected with an initial Velocity 20 m/s at 60° to the horizontal. Its velocity after 1 sec is

A body is projected vertically upwards with a velocity 'U'. It crosses a point in its journey at a height 'h' twice, just after 1 and 7 seconds. The value of U in ms^(-1) [ g=10 ms^(-2) ]

A ball is projected vertically up such that it passes thorugh a fixed point after a time t_(1) and t_(2) respectively. Find a. The height at which the point is located with respect to the point of projeciton b. The speed of projection of the ball. c. The velocity the ball at the time of passing through point P . d. (i) The maximum height reached by the balll relative to the point of projection A (ii) maximum height reached by the ball relative to point P under consideration. e. The average speed and average velocity of the ball during the motion from A to P for the time t_(1) and t_(2) respectively. .

A body of mass 2kg is projected from the ground with a velocity 20ms^(-1) at an angle 30^(@) with the vertical. If t_(1) is the time in seconds at which the body is projected and t_(2) is the time in seconds at which it reaches the ground, the change in momentum in kgms^(-1) during the time (t_(2)-t_(1)) is

A body is projected vertically upwards wth a velocity u=5m//s . After time t another body is projected vertically upward from the same point with a velocity v=3m//s . If they meet in minimum time duration measured from the projection of first body, then t=k/g sec find k (where g is gravitatio acceleration).

A body is projected with a velocity u at an angle of 60^(@) to the horizontal. The time interval after which it will be moving in a direction of 30^(@) to the horizontal is