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A car starts form rest and accelerates u...

A car starts form rest and accelerates uniformly for `10 s` to a velocity of `8 ms ^(-1)`. It then runs at a constant velocity an dis finally brought to rest in `64 m` with a constant retardation. The totla distance covered by the car is `584 m` Find the value of acceleration, retardation, and totl time taken.

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To solve the problem step by step, we will break it down into parts based on the motion of the car. ### Step 1: Find the acceleration The car starts from rest and accelerates uniformly for 10 seconds to a velocity of \(8 \, \text{m/s}\). Using the formula for acceleration: \[ v = u + at ...
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CENGAGE PHYSICS ENGLISH-KINEMATICS-1-Exercise 4.1
  1. a. If the velocity of a body is zero, does it mean that its accelerati...

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  2. Say Yes or No: a. Can an object moving towards north have accelerati...

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  3. Can a body have a. Zero instantaneous velocity and yet be accelerati...

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  4. A body moves at a speed of 100 ms^(-1) for 10 s and then moves at a sp...

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  5. A body moves in the southern direction for 10 s at the speed of 10 ms^...

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  6. A car trvelling at 108 km h^(-1) has its speed reduced to 36 km h^(-1)...

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  7. A car starts form rest and accelerates uniformly for 10 s to a velocit...

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  8. A body covera 10 m in the seconds second and 25 m in finfth second of ...

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  9. A body moving with uniform acceleration a straight line describes 25 m...

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  10. Two trains, each of length 100 mmoveing in opposite direction along pa...

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  11. Shows a particle starting from point A,travelling up to B with a speed...

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  12. A particle moving in a straight line covers half the distance with spe...

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  13. What will be the ratio of the distance moved by a freely falling body ...

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  14. Two balls of different masses (one lighter and other heaver) are throw...

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  15. A car runs at a constant speed on a circular track of radius 200 m, ta...

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  16. A train accelerates from rest at a constant rate a for time t(1)and th...

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  17. An athlete swims the length of 50 m pool in 20 s and makes the return ...

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