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A ball is dropped from the top of a towe...

A ball is dropped from the top of a tower of herght (h). It covers a destance of `h`//`2` in the last second of its motion. How long does the ball remain in air?

Text Solution

Verified by Experts

`h=(1)/(2)g n^(2)(h)/(2) =(1)/(2)g(n-1)^(2)`, where `n` is the total time taken.
Solving, we get
`n=(sqrt2)/(sqrt2-1) rArr n=((sqrt2)/(sqrt2-1)) ((sqrt2+1)/(sqrt2+1)) =2+sqrt2 s`.
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