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A body is allowed to fall from a height ...

A body is allowed to fall from a height of `10 m`. If the time taken for the first `50 m` is `t_(1)` and for the remaining `50 s`,is `t_(2)`.
Which is correct?

A

`t_(1)=t_(2)`

B

`t_(1) le t_(2)`

C

`t_(1) lt t_(2)`

D

`t_(1).t_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of a body falling freely under the influence of gravity. The body falls from a height of 10 m, and we need to find the time taken for the first 50 m (denoted as \( t_1 \)) and the time taken for the remaining distance (denoted as \( t_2 \)). ### Step-by-Step Solution: 1. **Understanding the motion**: The body is falling freely, so we can use the equations of motion under uniform acceleration due to gravity. The acceleration \( g \) is approximately \( 9.81 \, \text{m/s}^2 \). 2. **Finding \( t_1 \)**: The distance fallen in the first 50 m can be calculated using the equation: \[ s = \frac{1}{2} g t_1^2 \] where \( s = 50 \, \text{m} \). Rearranging the equation gives: \[ 50 = \frac{1}{2} g t_1^2 \implies t_1^2 = \frac{100}{g} \implies t_1 = \sqrt{\frac{100}{g}} = \frac{10}{\sqrt{g}} \] 3. **Finding the total time to fall 10 m**: The total distance fallen is 10 m, so we use the same equation: \[ 10 = \frac{1}{2} g T^2 \implies T^2 = \frac{20}{g} \implies T = \sqrt{\frac{20}{g}} = \frac{2\sqrt{5}}{\sqrt{g}} \] 4. **Finding \( t_2 \)**: The time taken to fall the remaining distance (10 m - 50 m = -40 m) can be calculated as: \[ t_2 = T - t_1 \] We need to find the time taken to fall the remaining distance of 50 m, which can be calculated as: \[ t_2 = T - t_1 = \frac{2\sqrt{5}}{\sqrt{g}} - \frac{10}{\sqrt{g}} = \frac{2\sqrt{5} - 10}{\sqrt{g}} \] 5. **Comparing \( t_1 \) and \( t_2 \)**: To compare \( t_1 \) and \( t_2 \), we can analyze the expressions: - \( t_1 = \frac{10}{\sqrt{g}} \) - \( t_2 = \frac{2\sqrt{5} - 10}{\sqrt{g}} \) Since \( \sqrt{5} \) is approximately 2.236, we find: \[ 2\sqrt{5} \approx 4.472 \implies 2\sqrt{5} - 10 \approx -5.528 \] Thus, \( t_2 \) is negative, indicating that \( t_1 > t_2 \). ### Conclusion: From our calculations, we conclude that \( t_1 > t_2 \). ### Final Answer: The correct statement is: \( t_1 > t_2 \). ---

To solve the problem, we need to analyze the motion of a body falling freely under the influence of gravity. The body falls from a height of 10 m, and we need to find the time taken for the first 50 m (denoted as \( t_1 \)) and the time taken for the remaining distance (denoted as \( t_2 \)). ### Step-by-Step Solution: 1. **Understanding the motion**: The body is falling freely, so we can use the equations of motion under uniform acceleration due to gravity. The acceleration \( g \) is approximately \( 9.81 \, \text{m/s}^2 \). 2. **Finding \( t_1 \)**: ...
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