The velocity-time graph of a particle moving along a straight line is shown is Fig. The rate of acceleration and deceleration is constant and it is equal to `5 m s^(-2)`. If the a average velocity during the motion is `20 m s^(-1)`, Then
.
The maximum velocity of the particle is .

Options

A. `20 m s^(-1)`
B. `25 m s^(-1)`
C. `30 m s^(-1)`
D. `40 m s^(-1)`

Answer

b

Explanation

Maximum velocity `=5 t=5 xx 5 =25 m s^(-1)`.