The range of a projectile at an angle `theta` is equal to half of the maximum range if thrown at the same speed. The angel of projection `theta` is given by

Explanation

To solve the problem, we need to find the angle of projection \( \theta \) such that the range of the projectile at this angle is equal to half of the maximum range when thrown at the same speed.

### Step 1: Understand the Range Formula
The range \( R \) of a projectile is given by the formula:
\[ R = \frac{u^2 \sin 2\theta}{g} \]
where:
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