The horizontal range of a projectile is `2 sqrt(3)` times its maximum height. Find the angle of projection.

Explanation

To solve the problem, we need to establish the relationship between the horizontal range and the maximum height of a projectile.

### Step-by-Step Solution:

1. **Understand the formulas:**
- The horizontal range \( R \) of a projectile is given by:
\[
R = \frac{u^2 \sin 2\theta}{g}
...