In this given reactions,

X and Y are respectively

Explanation

From garph (i) : `v_y = 0 at t = (1)/(2) s`, i.,e., time taken to reach maximum height `H` is
`t = (u_y)/(g) = (1)/(2) rArr u_y = 5 m s^-1`
From graph (2) , `v_y = 0 at x = 2 m`, i.,e., when the particle is at maximum height, its displacement along horizontal, `x = 2 m`.
`x = u_x xx t rArr 2 = u_x xx (1)/(2) rArr u_ x = 4 m s^-1`.