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A particle is projected from the ground ...

A particle is projected from the ground at `t = 0` so that on its way it just clears two vertical walls of equal height on the ground. The particle was projected with initial velocity `u` and at angle `theta` with the horiozontal. If the particle passes just grazing top of the wall at time `t = t_1 and t = t_2`, then calculate.
(a) the height of the wall.
(b) the time `t_1 and t_2` in terms of height of the wall.
Write the expression for calculating the range of this projectile and separation between the walls.

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To solve the problem step by step, we will break it down into parts as follows: ### Step 1: Understanding the Problem We have a particle projected from the ground at an angle θ with an initial velocity u. The particle just clears two vertical walls of equal height H at times t₁ and t₂. We need to find: (a) The height of the wall (H). (b) The times t₁ and t₂ in terms of H. (c) The expression for the range of the projectile. (d) The separation between the walls. ...
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