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The tangential acceleration of a particl...

The tangential acceleration of a particle moving in a circular path of radius `5 cm` is `2 m s^-2`. The angular velocity of the particle increases from `10 rad s^-1` to `20 rad s^-1` during some time. Find
(a) this duration od time and
(b) the number of revolutions completed during this time.

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AI Generated Solution

To solve the problem step by step, let's break it down into two parts as requested: (a) finding the duration of time and (b) finding the number of revolutions completed during that time. ### Given Data: - Radius of circular path, \( r = 5 \, \text{cm} = 0.05 \, \text{m} \) - Tangential acceleration, \( a_t = 2 \, \text{m/s}^2 \) - Initial angular velocity, \( \omega_1 = 10 \, \text{rad/s} \) - Final angular velocity, \( \omega_2 = 20 \, \text{rad/s} \) ...
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