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A gun is fired from a moving platform an...

A gun is fired from a moving platform and ranges of the shot are observed to be `R_1 and R_2` when the platform is moving forwards and backwards, respectively, with velocity `v_P`. Find the elevation of the gun `prop` in terms of the given quantities.

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To solve the problem, we need to analyze the motion of the projectile fired from a moving platform. Let's break it down step by step. ### Step 1: Define the Variables Let: - \( u \) = initial horizontal component of the velocity of the projectile with respect to the platform. - \( v \) = initial vertical component of the velocity of the projectile with respect to the platform. - \( v_P \) = velocity of the platform. - \( R_1 \) = range of the shot when the platform is moving forwards. - \( R_2 \) = range of the shot when the platform is moving backwards. - \( g \) = acceleration due to gravity. ### Step 2: Write the Range Equations When the gun is fired from the moving platform: 1. For the forward motion: \[ R_1 = \frac{2(u + v_P)v}{g} \] 2. For the backward motion: \[ R_2 = \frac{2(u - v_P)v}{g} \] ### Step 3: Add and Subtract the Range Equations Now, we can add and subtract these two equations to eliminate \( u \): - Adding: \[ R_1 + R_2 = \frac{2(u + v_P)v}{g} + \frac{2(u - v_P)v}{g} \] This simplifies to: \[ R_1 + R_2 = \frac{4uv}{g} \] - Subtracting: \[ R_1 - R_2 = \frac{2(u + v_P)v}{g} - \frac{2(u - v_P)v}{g} \] This simplifies to: \[ R_1 - R_2 = \frac{4v_Pv}{g} \] ### Step 4: Square the Difference of Ranges Now, we square the difference of the ranges: \[ (R_1 - R_2)^2 = \left(\frac{4v_Pv}{g}\right)^2 = \frac{16v_P^2v^2}{g^2} \] ### Step 5: Express \( v \) in Terms of \( R_1 \) and \( R_2 \) From the previous equations, we can express \( v \) in terms of \( R_1 \) and \( R_2 \): \[ v^2 = \frac{g^2(R_1 - R_2)^2}{16v_P^2} \] ### Step 6: Substitute \( v \) into the Range Equation Now, substitute \( v \) back into the equation for \( R_1 + R_2 \): \[ R_1 + R_2 = \frac{4u}{g} \cdot \sqrt{\frac{g^2(R_1 - R_2)^2}{16v_P^2}} \] This simplifies to: \[ R_1 + R_2 = \frac{4u(R_1 - R_2)}{4v_P} \Rightarrow R_1 + R_2 = \frac{u(R_1 - R_2)}{v_P} \] ### Step 7: Solve for the Elevation Angle The elevation angle \( \alpha \) can be expressed as: \[ \tan \alpha = \frac{v}{u} \] Using the expressions derived earlier, we can substitute: \[ \tan \alpha = \frac{g}{4v_P^2} \cdot \frac{R_1 - R_2}{R_1 + R_2} \] ### Final Expression for Elevation Thus, the elevation of the gun \( \alpha \) is given by: \[ \alpha = \tan^{-1} \left( \frac{g}{4v_P^2} \cdot \frac{R_1 - R_2}{R_1 + R_2} \right) \]

To solve the problem, we need to analyze the motion of the projectile fired from a moving platform. Let's break it down step by step. ### Step 1: Define the Variables Let: - \( u \) = initial horizontal component of the velocity of the projectile with respect to the platform. - \( v \) = initial vertical component of the velocity of the projectile with respect to the platform. - \( v_P \) = velocity of the platform. - \( R_1 \) = range of the shot when the platform is moving forwards. ...
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