A gun is firing bullets with velocity `v_0` by rotating it through `360^@` in the horizontal plane. The maximum area covered by the bullets is

Options

A. `pi((u^2)/(g))^2`
B. `pi((u^2)/(2 g))^2`
C. `pi((u)/(g))^2`
D. `pi((u)/(2 g))^2`

Answer

A

Explanation

(a) A bullet fired at angle `45^@` will fall maximum away, and all other bullets will fall with this bullet fired at `45^@`.
`R_(max) = (u^2)/(g)`
Maximum area covered `= pi R_(max)^2 = pi ((u^2)/(g))^2`.