Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projectin speed = u, angle projection from horizontal =`theta`)

Options

A. `(v)/(2) sqrt(1 + 2 cos^2 theta)`
B. `(v)/(2) sqrt(1 + 2 cos^2 theta)`
C. `(v)/(2) sqrt(1 + 3 cos^2 theta)`
D. `v cos theta`

Answer

C

Explanation

( c) Average velocity =`("Displacement")/("Time") = (sqrt(H^2 + R^2 //4))/(T//2)`
Putting the required values, we get
`v _(a v) = (v)/(2) (sqrt(1 + 3 cos^2 theta))`
.