A body of mass `m` is projected horizontally with a velocity `v` from the top of a tower of height `h` and it reaches the ground at a distance `x` from the foot of the tower. If a second body of mass `2 m` is projected horizontally from the top of a tower of height `2 h`, it reaches the ground at a distance `2x` from the foot of the tower. The horizontal veloctiy of the second body is.

Options

A. v
B. 2 v
C. `sqrt(2) v`
D. v//2

Answer

C

Explanation

( c) `x = v sqrt((2 h)/(g)), 2x = v' sqrt((2(2 h))/(g))` Solve to get `v' = (sqrt(2)) v`.