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From a tower of height 40 m, two bodies ...

From a tower of height `40 m`, two bodies are simultaneously projected horizontally in opposite direction, with velocities `2 m s^-1 and 8 ms^-1`. respectively.
The time taken for the displacement vectors of two bodies to be come perpendicular to each other is.

Text Solution

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The correct Answer is:
`(2)`
`80 = (1)/(2) xx 10`
`t^2 = (80)/(5) rArr t = 4`
`x_1 = 20 xx 4 = 80`
`x_2 = 30 xx 4 = 120`
Separation `x_1 + x_2 = 80 +120 = 200 m`.
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