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Two smooth block are placed at a smooth ...

Two smooth block are placed at a smooth corner as shown in fig. Both the bloks are having mass m. We apply a force F on the block m. Block A presses block B in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decreases, as we increases `F(theta = 37^(@)` with horizontal).

As soon as the pressing force on the horizontal wall by block B become zero, it will lose contact with ground. If the value of F further increases, block B will accelerate in the upward direction and simulaneously block A will towards right.
If the acceleration of block A is a rightwards, then the acceleration of block B will be

A

`(3a)/(4)`, upwards

B

`(4a)/(3)`, upwards

C

`(3a)/(5)`, upwards

D

`(4a)/(5)`, upwards

Text Solution

Verified by Experts

The correct Answer is:
A
To keep regular contact
`a sin theta = b cos theta`
`b= a tan theta = 3/4 a`
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