Home
Class 11
PHYSICS
A mass M is suspended as shown in fig. T...

A mass M is suspended as shown in fig. The system is in equilibrium. Assume pulleys to be massless. K is the force constant of the spring.

The extension produced in the spring is given by

A

`4Mg//K`

B

`Mg//K`

C

`2Mg//K`

D

`3Mg//K`

Text Solution

Verified by Experts

The correct Answer is:
A
`T=Mg`
`T_(1)=T+Mg = 2Mg`
`Kx = 2T_(1)`
or `x=(2T_(1))/(K) = (4Mg)/(K)`
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Assertion-reasoning|15 Videos

  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|10 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Integer type|1 Videos

Similar Questions

Explore conceptually related problems

A mass M is suspended as shown in fig. The system is in equilibrium. Assume pulleys to be massless. K is the force constant of the spring. Find the net tension force acting on the lower support.

A mass M is suspended as shown in fig. The system is in equilibrium. Assume pulleys to be massless. K is the force constant of the spring. If each of the pullies A and B has mass M, then find the net tension force acting on the lower support. Asumme pulleys to be frictionaless.

In the situation shown in figure all contact surfaces are smooth. The force constant of the spring is K. Two forces F are applied as shown. The maximum elongation produced in the spring is how many times of F//K (initially the spring is relaxed)?

System shown in fig is in equilibrium and at rest. The spring and string are massless now the string is cut. The acceleration of mass 2m and m just after the string is cut will be:

System shown in fig is in equilibrium and at rest. The spring and string are massless now the string is cut. The acceleration of mass 2m and m just after the string is cut will be:

The system is released from rest with both the springs in unstretched positions. Mass of each block is 1 kg and force constant of each spring is 10 N//m . Extension of horizontal spring in equilibrium is

A mass m is suspended from the two coupled springs connected in series. The force constant for springs are k_(1) and k_(2). The time period of the suspended mass will be

What would be the period of the free oscillations of the system shown here if mass M_(1) is pulled down a little force constant of the spring is k , mass of fixed pulley is negligible and movable pulley is smooth

Find the reading of spring balance as shown in fig. Assume that mass M in equilibrium. (All surfaces are smooth).

From the fixed pulley, masses 2 kg, 1 kg and 3 kg are suspended as shown is figure. Find the extension in the spring when acceleration of 3 kg and 1 kg is same if spring constant of the spring k = 100 N/m. (Take g = 10 ms^(-2) )

CENGAGE PHYSICS ENGLISH-NEWTON'S LAWS OF MOTION 1-Linked Comperhension
  1. In the arrangement shown in fig, pulleys D and E are small and frictio...

    Text Solution

    |

  2. In the arrangement shown in fig., all pulleys are smooth and massless....

    Text Solution

    |

  3. In the arrangement shown in fig., all pulleys are smooth and massless....

    Text Solution

    |

  4. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  5. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  6. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  7. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  8. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  9. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  10. Two containers of sand are arranged like the block as shown in fig. th...

    Text Solution

    |

  11. Two containers of sand are arranged like the block as shown in fig. th...

    Text Solution

    |

  12. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

    Text Solution

    |

  13. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

    Text Solution

    |

  14. A time varying force F=6t-2t^(2)N, at t=0 starts acting on a body of m...

    Text Solution

    |

  15. For the system shown in fig, there is no friction anywhere. Masses m(1...

    Text Solution

    |

  16. For the system shown in fig, there is no friction anywhere. Masses m(1...

    Text Solution

    |

  17. Two blocks of masses m(1) and m(2) are connected with a light spring o...

    Text Solution

    |

  18. A mass M is suspended as shown in fig. The system is in equilibrium. A...

    Text Solution

    |

  19. A mass M is suspended as shown in fig. The system is in equilibrium. A...

    Text Solution

    |

  20. A mass M is suspended as shown in fig. The system is in equilibrium. A...

    Text Solution

    |