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A force of vecF=2xhati+2hatj+3z^2hatk N ...

A force of `vecF=2xhati+2hatj+3z^2hatk N` is acting on a particle. Find the work done by this force in displacing the body from `(1, 2, 3)m` to `(3, 6, 1)m`.

A

(a) `-10J`

B

(b) `100J`

C

(c) `10J`

D

(d) `1J`

Text Solution

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The correct Answer is:
To find the work done by the force \(\vec{F} = 2x \hat{i} + 2 \hat{j} + 3z^2 \hat{k}\) when displacing the particle from the point \((1, 2, 3)\) to \((3, 6, 1)\), we will follow these steps: ### Step 1: Identify the displacement vector The displacement vector \(\vec{d}\) can be calculated as: \[ \vec{d} = (x_f - x_i) \hat{i} + (y_f - y_i) \hat{j} + (z_f - z_i) \hat{k} \] where \((x_i, y_i, z_i) = (1, 2, 3)\) and \((x_f, y_f, z_f) = (3, 6, 1)\). Calculating the components: \[ \vec{d} = (3 - 1) \hat{i} + (6 - 2) \hat{j} + (1 - 3) \hat{k} = 2 \hat{i} + 4 \hat{j} - 2 \hat{k} \] ### Step 2: Write the work done expression The work done \(W\) by the force during the displacement can be expressed as: \[ W = \int_C \vec{F} \cdot d\vec{r} \] where \(d\vec{r} = dx \hat{i} + dy \hat{j} + dz \hat{k}\). ### Step 3: Substitute the force and displacement The force \(\vec{F}\) varies with position, so we will express the work done in terms of the coordinates: \[ W = \int_{(1, 2, 3)}^{(3, 6, 1)} (2x \, dx + 2 \, dy + 3z^2 \, dz) \] ### Step 4: Set up the limits for integration We will integrate each component separately, with the limits for \(x\) from 1 to 3, for \(y\) from 2 to 6, and for \(z\) from 3 to 1. ### Step 5: Calculate the work done 1. **Integrate with respect to \(x\)**: \[ W_x = \int_{1}^{3} 2x \, dx = [x^2]_{1}^{3} = 3^2 - 1^2 = 9 - 1 = 8 \] 2. **Integrate with respect to \(y\)**: \[ W_y = \int_{2}^{6} 2 \, dy = [2y]_{2}^{6} = 2(6) - 2(2) = 12 - 4 = 8 \] 3. **Integrate with respect to \(z\)**: \[ W_z = \int_{3}^{1} 3z^2 \, dz = -\int_{1}^{3} 3z^2 \, dz = -[z^3]_{1}^{3} = -[27 - 1] = -26 \] ### Step 6: Combine the results Now, we sum the contributions from each component: \[ W = W_x + W_y + W_z = 8 + 8 - 26 = -10 \] ### Final Answer The work done by the force in displacing the body from \((1, 2, 3)\) to \((3, 6, 1)\) is: \[ \boxed{-10 \, \text{J}} \]

To find the work done by the force \(\vec{F} = 2x \hat{i} + 2 \hat{j} + 3z^2 \hat{k}\) when displacing the particle from the point \((1, 2, 3)\) to \((3, 6, 1)\), we will follow these steps: ### Step 1: Identify the displacement vector The displacement vector \(\vec{d}\) can be calculated as: \[ \vec{d} = (x_f - x_i) \hat{i} + (y_f - y_i) \hat{j} + (z_f - z_i) \hat{k} \] where \((x_i, y_i, z_i) = (1, 2, 3)\) and \((x_f, y_f, z_f) = (3, 6, 1)\). ...
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