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A man M(1) of mass 80 kg runs up a stair...

A man `M_(1)` of mass `80 kg` runs up a staircase in `15 s`. Another man `M_(2)` also of mass `80 kg` runs up the same staircase in `20 s`. The ratio of the power development by then will be:

A

(a) `1`

B

(b) `4/3`

C

(c) `16/9`

D

(d) None of the above

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The correct Answer is:
To find the ratio of the power developed by two men running up a staircase, we can follow these steps: ### Step 1: Understand the concept of power Power is defined as the rate at which work is done. Mathematically, it can be expressed as: \[ P = \frac{W}{t} \] where \( P \) is power, \( W \) is work done, and \( t \) is the time taken. ### Step 2: Identify the work done by both men Since both men have the same mass and are running up the same staircase, the work done \( W \) by both men will be the same. The work done against gravity when moving to a height \( h \) is given by: \[ W = mgh \] where \( m \) is mass, \( g \) is acceleration due to gravity, and \( h \) is the height of the staircase. ### Step 3: Calculate the power for each man Let: - \( M_1 \) (man 1) runs up the staircase in \( t_1 = 15 \) seconds. - \( M_2 \) (man 2) runs up the staircase in \( t_2 = 20 \) seconds. The power developed by man 1 is: \[ P_1 = \frac{W}{t_1} = \frac{W}{15} \] The power developed by man 2 is: \[ P_2 = \frac{W}{t_2} = \frac{W}{20} \] ### Step 4: Find the ratio of the powers To find the ratio of the powers developed by the two men, we can write: \[ \frac{P_1}{P_2} = \frac{\frac{W}{15}}{\frac{W}{20}} \] Since \( W \) is the same for both, it cancels out: \[ \frac{P_1}{P_2} = \frac{20}{15} \] ### Step 5: Simplify the ratio Now, simplifying the ratio: \[ \frac{P_1}{P_2} = \frac{20}{15} = \frac{4}{3} \] ### Conclusion Thus, the ratio of the power developed by man 1 to man 2 is: \[ P_1 : P_2 = 4 : 3 \] ---

To find the ratio of the power developed by two men running up a staircase, we can follow these steps: ### Step 1: Understand the concept of power Power is defined as the rate at which work is done. Mathematically, it can be expressed as: \[ P = \frac{W}{t} \] where \( P \) is power, \( W \) is work done, and \( t \) is the time taken. ### Step 2: Identify the work done by both men ...
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CENGAGE PHYSICS ENGLISH-WORK, POWER & ENERGY-Single Correct
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