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The speed v reached by a car of mass m i...

The speed v reached by a car of mass m in travelling a distance x, driven with constant power P, is given by

A

(a) `v=(3xP)/(m)`

B

(b) `v=((3xP)/(m))^(1//2)`

C

(c) `v=((3xP)/(m))^(1//3)`

D

(d) `v=((3xP)/(m))^2`

Text Solution

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The correct Answer is:
To solve the problem of finding the speed \( v \) reached by a car of mass \( m \) traveling a distance \( x \) while being driven with constant power \( P \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between power, force, and velocity**: The power \( P \) delivered by the car can be expressed as: \[ P = F \cdot v \] where \( F \) is the force acting on the car and \( v \) is its velocity. 2. **Express force in terms of mass and acceleration**: The force \( F \) can also be expressed using Newton's second law: \[ F = m \cdot a \] where \( a \) is the acceleration of the car. 3. **Relate acceleration to velocity and distance**: We know that acceleration \( a \) can be expressed as: \[ a = \frac{dv}{dt} = \frac{dv}{dx} \cdot v \] Thus, we can rewrite the power equation as: \[ P = m \cdot a \cdot v = m \cdot \left(\frac{dv}{dx} \cdot v\right) \cdot v = m \cdot v \cdot \frac{dv}{dx} \] 4. **Rearranging the equation**: Rearranging the equation gives: \[ P = m \cdot v \cdot \frac{dv}{dx} \] From this, we can isolate \( \frac{dv}{dx} \): \[ \frac{dv}{dx} = \frac{P}{m \cdot v} \] 5. **Integrate both sides**: We need to integrate both sides. The left side will be integrated with respect to \( v \) from \( 0 \) to \( v \) and the right side with respect to \( x \) from \( 0 \) to \( x \): \[ \int_0^v v \, dv = \int_0^x \frac{P}{m} \, dx \] 6. **Perform the integration**: The left side integrates to: \[ \frac{v^2}{2} \bigg|_0^v = \frac{v^2}{2} \] The right side integrates to: \[ \frac{P}{m} \cdot x \bigg|_0^x = \frac{P}{m} \cdot x \] 7. **Set the two integrals equal**: Thus, we have: \[ \frac{v^2}{2} = \frac{P}{m} \cdot x \] 8. **Solve for \( v \)**: Multiplying both sides by 2 gives: \[ v^2 = \frac{2Px}{m} \] Taking the square root of both sides results in: \[ v = \sqrt{\frac{2Px}{m}} \] 9. **Final expression**: To express \( v \) in terms of \( P \), \( x \), and \( m \): \[ v = \sqrt{\frac{2Px}{m}} \] ### Final Answer: The speed \( v \) reached by a car of mass \( m \) traveling a distance \( x \) driven with constant power \( P \) is given by: \[ v = \sqrt{\frac{2Px}{m}} \]

To solve the problem of finding the speed \( v \) reached by a car of mass \( m \) traveling a distance \( x \) while being driven with constant power \( P \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between power, force, and velocity**: The power \( P \) delivered by the car can be expressed as: \[ P = F \cdot v ...
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CENGAGE PHYSICS ENGLISH-WORK, POWER & ENERGY-Single Correct
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