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Given vecF=(xy^2)hati+(x^2y)hatjN. The w...

Given `vecF=(xy^2)hati+(x^2y)hatjN`. The work done by `vecF` when a particle is taken along the semicircular path OAB where the coordinates of B are `(4,0)` is

A

(a) `65/3J`

B

(b) `75/2J`

C

(c) `73/4J`

D

(d) Zero

Text Solution

Verified by Experts

The correct Answer is:
D
Given `vecF=(xy)^2hati(x^2y)hatj`
`W=int F_xdx+intF_ydy`
`=intxy^2dx+intx^2ydy`
`=1/2int d(x^2y^2)=[(x^2y^2)/(2)]_(0,0)^(4,0)=0`
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