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A 1kg stone at the end of 1m long string...

A `1kg` stone at the end of `1m` long string is whirled in a vertical circle at a constant speed of `4m//s`. The tension in the string is `6N`, when the stone is at `(g=10m//s^(2))`

A

(a) At the top of the circle

B

(b) At the bottom of the circle

C

(c) Half way down

D

(d) None of the above

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the forces acting on the stone when it is at the top of the vertical circle. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Forces Acting on the Stone When the stone is at the top of the vertical circle, two main forces act on it: - The gravitational force (weight) acting downwards: \( W = mg \) - The centripetal force required to keep the stone moving in a circle, which is provided by the tension in the string and the weight of the stone. ### Step 2: Calculate the Weight of the Stone Given: - Mass of the stone, \( m = 1 \, \text{kg} \) - Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \) The weight of the stone is calculated as: \[ W = mg = 1 \, \text{kg} \times 10 \, \text{m/s}^2 = 10 \, \text{N} \] ### Step 3: Calculate the Centripetal Force The centripetal force required to keep the stone moving in a circle is given by: \[ F_c = \frac{mv^2}{r} \] Where: - \( v = 4 \, \text{m/s} \) (the speed of the stone) - \( r = 1 \, \text{m} \) (the radius of the circle) Substituting the values: \[ F_c = \frac{1 \, \text{kg} \times (4 \, \text{m/s})^2}{1 \, \text{m}} = \frac{1 \times 16}{1} = 16 \, \text{N} \] ### Step 4: Analyze the Forces at the Top of the Circle At the top of the circle, the tension in the string \( T \) and the weight of the stone \( W \) together provide the necessary centripetal force: \[ F_c = T + W \] Given that the tension \( T = 6 \, \text{N} \) when the stone is at the top, we can substitute the known values: \[ 16 \, \text{N} = T + 10 \, \text{N} \] Substituting \( T = 6 \, \text{N} \): \[ 16 \, \text{N} = 6 \, \text{N} + 10 \, \text{N} \] This confirms that the forces are balanced correctly. ### Step 5: Conclusion The tension in the string is 6 N when the stone is at the top of the vertical circle. ### Final Answer The tension in the string is 6 N when the stone is at the top of the circle. ---

To solve the problem, we need to analyze the forces acting on the stone when it is at the top of the vertical circle. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Forces Acting on the Stone When the stone is at the top of the vertical circle, two main forces act on it: - The gravitational force (weight) acting downwards: \( W = mg \) - The centripetal force required to keep the stone moving in a circle, which is provided by the tension in the string and the weight of the stone. ### Step 2: Calculate the Weight of the Stone ...
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