A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If `W_(nc)` and `W_c` are the work done by non-conservative and conservative forces present in the system, respectively, `DeltaU` is the change in potential energy and `Deltak` is the change in kinetic energy, then

Options

A. (a) `W_(nc)-DeltaU=Deltak`
B. (b) `W_c=-DeltaU`
C. (c) `W_(nc)+W_(c)=Deltak`
D. (d) `W_(nc)-DeltaU=-Deltak`

Answer

A, B, C

Explanation

According to the work-energy theorem for a non-conservative system, we have `W_c+W_(nc)=DeltaK`
Also, we know that the work done by a conservative force equals the decrease in potential energy, so `W_c=-DeltaU`
`W_(nc)-DeltaU=DeltaK`