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A spring of force constant k is cut into...

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

A

(a) `(2/3)k`

B

(b) `(3/2)k`

C

(c) `3k`

D

(d) `6k`

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To solve the problem, we need to determine the spring constant of the longer piece after a spring of force constant \( k \) is cut into two pieces such that one piece is double the length of the other. ### Step-by-Step Solution: 1. **Identify the lengths of the pieces**: Let the length of the shorter piece be \( L_1 \) and the longer piece be \( L_2 \). According to the problem, \( L_2 = 2L_1 \). 2. **Express the total length**: The total length of the original spring is: \[ L = L_1 + L_2 = L_1 + 2L_1 = 3L_1 \] From this, we can express \( L_1 \) in terms of \( L \): \[ L_1 = \frac{L}{3} \] 3. **Determine the length of the longer piece**: Now substituting \( L_1 \) into the equation for \( L_2 \): \[ L_2 = 2L_1 = 2 \left(\frac{L}{3}\right) = \frac{2L}{3} \] 4. **Relate the spring constants**: The spring constant \( k \) for the original spring relates to the spring constants of the two pieces. The relationship between the spring constants and lengths is given by: \[ k_1 L_1 = k_2 L_2 \] where \( k_1 \) is the spring constant of the shorter piece and \( k_2 \) is the spring constant of the longer piece. 5. **Substituting the lengths**: Substitute \( L_1 \) and \( L_2 \) into the equation: \[ k_1 \left(\frac{L}{3}\right) = k_2 \left(\frac{2L}{3}\right) \] 6. **Simplifying the equation**: Cancel \( \frac{L}{3} \) from both sides (assuming \( L \neq 0 \)): \[ k_1 = 2k_2 \] 7. **Express \( k_1 \) in terms of \( k \)**: Since the original spring has a spring constant \( k \), we can express \( k_1 \) in terms of \( k \). The spring constant of the shorter piece \( k_1 \) can be related to the original spring constant: \[ k_1 = \frac{k \cdot L}{L_1} = \frac{k \cdot L}{\frac{L}{3}} = 3k \] 8. **Finding \( k_2 \)**: Now substituting \( k_1 = 3k \) back into the equation \( k_1 = 2k_2 \): \[ 3k = 2k_2 \implies k_2 = \frac{3k}{2} \] 9. **Conclusion**: Therefore, the spring constant of the longer piece \( k_2 \) is: \[ k_2 = \frac{3k}{2} \] ### Final Answer: The spring constant of the longer piece is \( \frac{3k}{2} \).

To solve the problem, we need to determine the spring constant of the longer piece after a spring of force constant \( k \) is cut into two pieces such that one piece is double the length of the other. ### Step-by-Step Solution: 1. **Identify the lengths of the pieces**: Let the length of the shorter piece be \( L_1 \) and the longer piece be \( L_2 \). According to the problem, \( L_2 = 2L_1 \). 2. **Express the total length**: ...
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