The hero of a stunt film fires 50 g bullets from a machine gun, each at a speed of 1.0 km/s. If he fires 20 bullets in 4 seconds. What average force does he exert against the machine gun during this period?
Text Solution
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The momentum of each bullet `(0.050kg)(1000m//s)=50kgm//s`. ltbr The gun is imparted this much of momentum by each bullet fired. Thus, the rate of change of momentum of the gun is `50 kg m/s xx20)/4s=250N`. In order to hold the gun, the hero must exert a force of `250 N` against the gun.
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CENGAGE PHYSICS ENGLISH-CENTRE OF MASS-INTEGER_TYPE