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A rope thrown over a pulley has a on one...

A rope thrown over a pulley has a on one of its ends and a counterbalancing mass `M` on its other end. The man whose mass is `m`, climbs upwards by `vec/_\r` relative to the ladder and then stops. Ignoring masses of the pulley and the rope, as well as the friction the pulley axis, find the displacement of the centre of mass of this system.

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To solve the problem of finding the displacement of the center of mass of the system when the man climbs up the ladder, we will follow these steps: ### Step 1: Understand the System We have a man of mass \( m \) climbing a ladder, which is connected to a counterbalancing mass \( M \) via a rope over a pulley. The man climbs a distance \( \Delta r \) relative to the ladder. ### Step 2: Define Displacements - Let the displacement of the man relative to the ground be \( x_m \). - The displacement of the counterbalancing mass \( M \) will be \( x_M \). ...
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